2019 4marks Catholic High P6 Paper2 SA2 P6 / Catholic High / 2019 / SA2 / Paper 2 – Q12 [4 marks] Question: In the figure, ABGH and DEFH are parallelograms. AHF is a straight line. ∠GHA = 107°, ∠FHC = 114° and ∠HGF = 75°.(a) Find ∠GHC.(b) Find ∠EFG. Solution: Similar Posts P6 / Nanyang / 2019 / SA2 / Paper 2 – Q14 [4 marks] P6 / Catholic High / 2018 / SA1 / Paper 1 – Q23 [2 marks]