Question:
The figure below is made up of 2 overlapping semicircles and a quadrant in a square of sides 24 cm. Find the total area of the parts that are shaded. Take π = 3.14
Solution:
Empowering Students and Parents with Solutions
Empowering Students and Parents with Solutions
![P6 / Henry Park / 2021 / SA2 / Paper 1 –
Q20 [1 mark]](https://i0.wp.com/sgprimaths.com/wp-content/uploads/2022/06/P6_SA2_2021_Henry_Park_Paper1_Q20-Qns.jpg?resize=400%2C260&ssl=1)
![P6 / Henry Park / 2019 / SA2 / Paper 2 – Q04 [2 marks]](https://i0.wp.com/sgprimaths.com/wp-content/uploads/2020/06/P6_Henry_Park_2019_Prelims_Paper2_Q04-Qns.jpg?resize=400%2C260&ssl=1)
Hi! I was looking for another question and chanced on your site. If you don’t mind me sharing, this qn can b solved by cut n paste. Cut the bottom leaf in 2, paste it to fit next to the big shaded part.
1) find area of top half of sq aka triangle.
2) find area of the topmost quadrant
3) ans 1 – 2. Done. Thank you
Hi C!
That is a shorter and more elegant solution than what I have posted!
Thanks for the alternative solution =)
I think this can be further simplified.
Area of half square – area of quarter circle
= a^2/2-πr^2/4
= 288 – 113.04
= 174.96 cm^2
(a = 24 , π=3.14, r=12)